Base | Representation |
---|---|
bin | 10100100111010110… |
… | …00011010100100101 |
3 | 1001120022101210020120 |
4 | 22103223003110211 |
5 | 140131233034031 |
6 | 5030114152153 |
7 | 541155644466 |
oct | 122353032445 |
9 | 31508353216 |
10 | 11067471141 |
11 | 476a331971 |
12 | 218a582659 |
13 | 1074bbc0bc |
14 | 76dc34d6d |
15 | 44b96aa96 |
hex | 293ac3525 |
11067471141 has 4 divisors (see below), whose sum is σ = 14756628192. Its totient is φ = 7378314092.
The previous prime is 11067471113. The next prime is 11067471143. The reversal of 11067471141 is 14117476011.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14117476011 = 3 ⋅4705825337.
It is a cyclic number.
It is not a de Polignac number, because 11067471141 - 29 = 11067470629 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11067471143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1844578521 + ... + 1844578526.
It is an arithmetic number, because the mean of its divisors is an integer number (3689157048).
Almost surely, 211067471141 is an apocalyptic number.
It is an amenable number.
11067471141 is a deficient number, since it is larger than the sum of its proper divisors (3689157051).
11067471141 is an equidigital number, since it uses as much as digits as its factorization.
11067471141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3689157050.
The product of its (nonzero) digits is 4704, while the sum is 33.
The spelling of 11067471141 in words is "eleven billion, sixty-seven million, four hundred seventy-one thousand, one hundred forty-one".
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