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11074918000117 is a prime number
BaseRepresentation
bin1010000100101001010010…
…0011011010010111110101
31110012202022002002102001111
42201022110203122113311
52422422413002000432
635315425212155021
72222064535524616
oct241122443322765
943182262072044
1011074918000117
11358a934541294
1212aa487768a71
1362448b71983a
142a40593c5c0d
1514313d925347
hexa12948da5f5

11074918000117 has 2 divisors, whose sum is σ = 11074918000118. Its totient is φ = 11074918000116.

The previous prime is 11074918000079. The next prime is 11074918000141. The reversal of 11074918000117 is 71100081947011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9404532355761 + 1670385644356 = 3066681^2 + 1292434^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11074918000117 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11074918000117.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11074918000187) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5537459000058 + 5537459000059.

It is an arithmetic number, because the mean of its divisors is an integer number (5537459000059).

Almost surely, 211074918000117 is an apocalyptic number.

It is an amenable number.

11074918000117 is a deficient number, since it is larger than the sum of its proper divisors (1).

11074918000117 is an equidigital number, since it uses as much as digits as its factorization.

11074918000117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14112, while the sum is 40.

Adding to 11074918000117 its reverse (71100081947011), we get a palindrome (82174999947128).

The spelling of 11074918000117 in words is "eleven trillion, seventy-four billion, nine hundred eighteen million, one hundred seventeen", and thus it is an aban number.