1108099487941 has 2 divisors, whose sum is σ = 1108099487942. Its totient is φ = 1108099487940.

The previous prime is 1108099487861. The next prime is 1108099487983. The reversal of 1108099487941 is 1497849908011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1085795260225 + 22304227716 = 1042015^2 + 149346^2 .

It is a cyclic number.

It is not a de Polignac number, because 1108099487941 - 2¹¹ = 1108099485893 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1108099487941.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1108099407941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 554049743970 + 554049743971.

It is an arithmetic number, because the mean of its divisors is an integer number (554049743971).

Almost surely, 2^{1108099487941} is an apocalyptic number.

It is an amenable number.

1108099487941 is a deficient number, since it is larger than the sum of its proper divisors (1).

1108099487941 is an equidigital number, since it uses as much as digits as its factorization.

1108099487941 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5225472, while the sum is 61.

The spelling of 1108099487941 in words is "one trillion, one hundred eight billion, ninety-nine million, four hundred eighty-seven thousand, nine hundred forty-one".