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11081113 is a prime number
BaseRepresentation
bin101010010001…
…010110011001
3202211222102121
4222101112121
510314043423
61033301241
7163121311
oct52212631
922758377
1011081113
11628944a
123864821
1323ac994
141686441
15e8d45d
hexa91599

11081113 has 2 divisors, whose sum is σ = 11081114. Its totient is φ = 11081112.

The previous prime is 11081107. The next prime is 11081117. The reversal of 11081113 is 31118011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8684809 + 2396304 = 2947^2 + 1548^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11081113 is a prime.

It is not a weakly prime, because it can be changed into another prime (11081117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5540556 + 5540557.

It is an arithmetic number, because the mean of its divisors is an integer number (5540557).

Almost surely, 211081113 is an apocalyptic number.

It is an amenable number.

11081113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11081113 is an equidigital number, since it uses as much as digits as its factorization.

11081113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 16.

The square root of 11081113 is about 3328.8305754424. The cubic root of 11081113 is about 222.9433184582.

Adding to 11081113 its reverse (31118011), we get a palindrome (42199124).

It can be divided in two parts, 11081 and 113, that multiplied together give a triangular number (1252153 = T1582).

The spelling of 11081113 in words is "eleven million, eighty-one thousand, one hundred thirteen".