Base | Representation |
---|---|
bin | 110011101011110011… |
… | …1110010000011101101 |
3 | 101121111012111012011102 |
4 | 1213113213302003231 |
5 | 3304302334244433 |
6 | 122553333332445 |
7 | 11006322663344 |
oct | 1472747620355 |
9 | 347435435142 |
10 | 110991712493 |
11 | 43086a23412 |
12 | 19616a97125 |
13 | a60aac4b2c |
14 | 552cbb4b5b |
15 | 2d491dd4e8 |
hex | 19d79f20ed |
110991712493 has 2 divisors, whose sum is σ = 110991712494. Its totient is φ = 110991712492.
The previous prime is 110991712487. The next prime is 110991712541. The reversal of 110991712493 is 394217199011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 110767821124 + 223891369 = 332818^2 + 14963^2 .
It is a cyclic number.
It is not a de Polignac number, because 110991712493 - 210 = 110991711469 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110991712483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55495856246 + 55495856247.
It is an arithmetic number, because the mean of its divisors is an integer number (55495856247).
Almost surely, 2110991712493 is an apocalyptic number.
It is an amenable number.
110991712493 is a deficient number, since it is larger than the sum of its proper divisors (1).
110991712493 is an equidigital number, since it uses as much as digits as its factorization.
110991712493 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 122472, while the sum is 47.
The spelling of 110991712493 in words is "one hundred ten billion, nine hundred ninety-one million, seven hundred twelve thousand, four hundred ninety-three".
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