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11100000083 is a prime number
BaseRepresentation
bin10100101011001110…
…01000111101010011
31001122120121102120012
422111213020331103
5140213100000313
65033235305135
7542032305164
oct122547107523
931576542505
1011100000083
11478672a397
12219944b1ab
13107b86b1b3
147742a176b
1544e743da8
hex2959c8f53

11100000083 has 2 divisors, whose sum is σ = 11100000084. Its totient is φ = 11100000082.

The previous prime is 11100000071. The next prime is 11100000097. The reversal of 11100000083 is 38000000111.

It is an a-pointer prime, because the next prime (11100000097) can be obtained adding 11100000083 to its sum of digits (14).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11100000083 - 26 = 11100000019 is a prime.

It is not a weakly prime, because it can be changed into another prime (11100000053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550000041 + 5550000042.

It is an arithmetic number, because the mean of its divisors is an integer number (5550000042).

Almost surely, 211100000083 is an apocalyptic number.

11100000083 is a deficient number, since it is larger than the sum of its proper divisors (1).

11100000083 is an equidigital number, since it uses as much as digits as its factorization.

11100000083 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 11100000083 its reverse (38000000111), we get a palindrome (49100000194).

The spelling of 11100000083 in words is "eleven billion, one hundred million, eighty-three", and thus it is an aban number.