11100000113 has 2 divisors, whose sum is σ = 11100000114. Its totient is φ = 11100000112.

The previous prime is 11100000101. The next prime is 11100000157. The reversal of 11100000113 is 31100000111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9850165504 + 1249834609 = 99248^2 + 35353^2 .

It is a cyclic number.

It is not a de Polignac number, because 11100000113 - 2⁴ = 11100000097 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11100000113.

It is not a weakly prime, because it can be changed into another prime (11100000193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550000056 + 5550000057.

It is an arithmetic number, because the mean of its divisors is an integer number (5550000057).

Almost surely, 2^11100000113 is an apocalyptic number.

It is an amenable number.

11100000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11100000113 is an equidigital number, since it uses as much as digits as its factorization.

11100000113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3, while the sum is 8.

Adding to 11100000113 its reverse (31100000111), we get a palindrome (42200000224).

The spelling of 11100000113 in words is "eleven billion, one hundred million, one hundred thirteen", and thus it is an aban number.