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1110000041041 is a prime number
BaseRepresentation
bin10000001001110001001…
…010000111110001010001
310221010002210220111011011
4100021301022013301101
5121141240002303131
62205532121050521
7143123556450103
oct20116112076121
93833083814134
101110000041041
113988260a3921
1215b160926a41
13808987ab318
143ba1d63b573
151dd1886b0b1
hex10271287c51

1110000041041 has 2 divisors, whose sum is σ = 1110000041042. Its totient is φ = 1110000041040.

The previous prime is 1110000041011. The next prime is 1110000041113. The reversal of 1110000041041 is 1401400000111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1082596549441 + 27403491600 = 1040479^2 + 165540^2 .

It is a cyclic number.

It is not a de Polignac number, because 1110000041041 - 213 = 1110000032849 is a prime.

It is a super-2 number, since 2×11100000410412 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1110000041011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555000020520 + 555000020521.

It is an arithmetic number, because the mean of its divisors is an integer number (555000020521).

Almost surely, 21110000041041 is an apocalyptic number.

It is an amenable number.

1110000041041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1110000041041 is an equidigital number, since it uses as much as digits as its factorization.

1110000041041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16, while the sum is 13.

Adding to 1110000041041 its reverse (1401400000111), we get a palindrome (2511400041152).

The spelling of 1110000041041 in words is "one trillion, one hundred ten billion, forty-one thousand, forty-one".