111000131113 has 4 divisors (see below), whose sum is σ = 111031858000. Its totient is φ = 110968404228.

The previous prime is 111000131101. The next prime is 111000131147. The reversal of 111000131113 is 311131000111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311131000111 = 47 ⋅6619808513.

It is a cyclic number.

It is not a de Polignac number, because 111000131113 - 2³³ = 102410196521 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 111000131093 and 111000131102.

It is not an unprimeable number, because it can be changed into a prime (111000131413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15858195 + ... + 15865192.

It is an arithmetic number, because the mean of its divisors is an integer number (27757964500).

Almost surely, 2^111000131113 is an apocalyptic number.

It is an amenable number.

111000131113 is a deficient number, since it is larger than the sum of its proper divisors (31726887).

111000131113 is an equidigital number, since it uses as much as digits as its factorization.

111000131113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31726886.

The product of its (nonzero) digits is 9, while the sum is 13.

Adding to 111000131113 its reverse (311131000111), we get a palindrome (422131131224).

The spelling of 111000131113 in words is "one hundred eleven billion, one hundred thirty-one thousand, one hundred thirteen".