Base | Representation |
---|---|
bin | 1010000110000110110001… |
… | …0101101010111010010111 |
3 | 1110022011001222222020012011 |
4 | 2201201230111222322113 |
5 | 2423330311324103413 |
6 | 35335135311405051 |
7 | 2223643446465154 |
oct | 241415425527227 |
9 | 43264058866164 |
10 | 11100013112983 |
11 | 359a542030a93 |
12 | 12b330bb23787 |
13 | 62695a875252 |
14 | 2a535a24b22b |
15 | 143b0bb3433d |
hex | a186c56ae97 |
11100013112983 has 2 divisors, whose sum is σ = 11100013112984. Its totient is φ = 11100013112982.
The previous prime is 11100013112959. The next prime is 11100013113121. The reversal of 11100013112983 is 38921131000111.
11100013112983 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (38921131000111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11100013112983 - 221 = 11100011015831 is a prime.
It is a super-2 number, since 2×111000131129832 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11100013112933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550006556491 + 5550006556492.
It is an arithmetic number, because the mean of its divisors is an integer number (5550006556492).
Almost surely, 211100013112983 is an apocalyptic number.
11100013112983 is a deficient number, since it is larger than the sum of its proper divisors (1).
11100013112983 is an equidigital number, since it uses as much as digits as its factorization.
11100013112983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 31.
The spelling of 11100013112983 in words is "eleven trillion, one hundred billion, thirteen million, one hundred twelve thousand, nine hundred eighty-three".
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