Base | Representation |
---|---|
bin | 10000001001110001010… |
… | …010000110010000011001 |
3 | 10221010002221211201101211 |
4 | 100021301102012100121 |
5 | 121141241021210433 |
6 | 2205532233543121 |
7 | 143123613306136 |
oct | 20116122062031 |
9 | 3833087751354 |
10 | 1110002131993 |
11 | 3988272a1887 |
12 | 15b161574aa1 |
13 | 80899060c81 |
14 | 3ba1da2358d |
15 | 1dd18b308cd |
hex | 10271486419 |
1110002131993 has 2 divisors, whose sum is σ = 1110002131994. Its totient is φ = 1110002131992.
The previous prime is 1110002131937. The next prime is 1110002132119. The reversal of 1110002131993 is 3991312000111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 723499945744 + 386502186249 = 850588^2 + 621693^2 .
It is a cyclic number.
It is not a de Polignac number, because 1110002131993 - 29 = 1110002131481 is a prime.
It is not a weakly prime, because it can be changed into another prime (1110002531993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555001065996 + 555001065997.
It is an arithmetic number, because the mean of its divisors is an integer number (555001065997).
Almost surely, 21110002131993 is an apocalyptic number.
It is an amenable number.
1110002131993 is a deficient number, since it is larger than the sum of its proper divisors (1).
1110002131993 is an equidigital number, since it uses as much as digits as its factorization.
1110002131993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1458, while the sum is 31.
The spelling of 1110002131993 in words is "one trillion, one hundred ten billion, two million, one hundred thirty-one thousand, nine hundred ninety-three".
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