Base | Representation |
---|---|
bin | 10000001001110001010… |
… | …011100111111010011001 |
3 | 10221010002222121001002122 |
4 | 100021301103213322121 |
5 | 121141241122010433 |
6 | 2205532250311025 |
7 | 143123616563255 |
oct | 20116123477231 |
9 | 3833088531078 |
10 | 1110002531993 |
11 | 398827545363 |
12 | 15b161728475 |
13 | 80899171064 |
14 | 3ba1dac9265 |
15 | 1dd18bae198 |
hex | 102714e7e99 |
1110002531993 has 2 divisors, whose sum is σ = 1110002531994. Its totient is φ = 1110002531992.
The previous prime is 1110002531987. The next prime is 1110002531999. The reversal of 1110002531993 is 3991352000111.
It is a balanced prime because it is at equal distance from previous prime (1110002531987) and next prime (1110002531999).
It can be written as a sum of positive squares in only one way, i.e., 1042914797824 + 67087734169 = 1021232^2 + 259013^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1110002531993 is a prime.
It is not a weakly prime, because it can be changed into another prime (1110002531999) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555001265996 + 555001265997.
It is an arithmetic number, because the mean of its divisors is an integer number (555001265997).
Almost surely, 21110002531993 is an apocalyptic number.
It is an amenable number.
1110002531993 is a deficient number, since it is larger than the sum of its proper divisors (1).
1110002531993 is an equidigital number, since it uses as much as digits as its factorization.
1110002531993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7290, while the sum is 35.
The spelling of 1110002531993 in words is "one trillion, one hundred ten billion, two million, five hundred thirty-one thousand, nine hundred ninety-three".
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