11100043313 has 4 divisors (see below), whose sum is σ = 11100264048. Its totient is φ = 11099822580.

The previous prime is 11100043309. The next prime is 11100043373. The reversal of 11100043313 is 31334000111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31334000111 = 43 ⋅728697677.

It is a cyclic number.

It is not a de Polignac number, because 11100043313 - 2² = 11100043309 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11100043291 and 11100043300.

It is not an unprimeable number, because it can be changed into a prime (11100043373) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5870 + ... + 149112.

It is an arithmetic number, because the mean of its divisors is an integer number (2775066012).

Almost surely, 2^11100043313 is an apocalyptic number.

It is an amenable number.

11100043313 is a deficient number, since it is larger than the sum of its proper divisors (220735).

11100043313 is an equidigital number, since it uses as much as digits as its factorization.

11100043313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 220734.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 11100043313 its reverse (31334000111), we get a palindrome (42434043424).

The spelling of 11100043313 in words is "eleven billion, one hundred million, forty-three thousand, three hundred thirteen".