Base | Representation |
---|---|
bin | 10100101011001110… |
… | …11000110101111011 |
3 | 1001122120201201210222 |
4 | 22111213120311323 |
5 | 140213104041042 |
6 | 5033240530255 |
7 | 542032665653 |
oct | 122547306573 |
9 | 31576651728 |
10 | 11100065147 |
11 | 4786774266 |
12 | 219948098b |
13 | 107b8919b2 |
14 | 7742bb363 |
15 | 44e7582d2 |
hex | 2959d8d7b |
11100065147 has 2 divisors, whose sum is σ = 11100065148. Its totient is φ = 11100065146.
The previous prime is 11100065129. The next prime is 11100065159. The reversal of 11100065147 is 74156000111.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (74156000111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11100065147 - 214 = 11100048763 is a prime.
It is a super-2 number, since 2×111000651472 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11100062147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550032573 + 5550032574.
It is an arithmetic number, because the mean of its divisors is an integer number (5550032574).
Almost surely, 211100065147 is an apocalyptic number.
11100065147 is a deficient number, since it is larger than the sum of its proper divisors (1).
11100065147 is an equidigital number, since it uses as much as digits as its factorization.
11100065147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 840, while the sum is 26.
Adding to 11100065147 its reverse (74156000111), we get a palindrome (85256065258).
The spelling of 11100065147 in words is "eleven billion, one hundred million, sixty-five thousand, one hundred forty-seven".
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