111001044001 has 4 divisors (see below), whose sum is σ = 111002035392. Its totient is φ = 111000052612.

The previous prime is 111001043969. The next prime is 111001044079. The reversal of 111001044001 is 100440100111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 111001044001 - 2⁵ = 111001043969 is a prime.

It is a super-3 number, since 3×111001044001³ (a number of 34 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (111001041001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 302701 + ... + 560026.

It is an arithmetic number, because the mean of its divisors is an integer number (27750508848).

Almost surely, 2^111001044001 is an apocalyptic number.

It is an amenable number.

111001044001 is a deficient number, since it is larger than the sum of its proper divisors (991391).

111001044001 is an equidigital number, since it uses as much as digits as its factorization.

111001044001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 991390.

The product of its (nonzero) digits is 16, while the sum is 13.

Adding to 111001044001 its reverse (100440100111), we get a palindrome (211441144112).

The spelling of 111001044001 in words is "one hundred eleven billion, one million, forty-four thousand, one".