Base | Representation |
---|---|
bin | 1010000110000111001000… |
… | …1011000111110011101011 |
3 | 1110022011022211011222002112 |
4 | 2201201302023013303223 |
5 | 2423331011404323201 |
6 | 35335153125552535 |
7 | 2223646045554236 |
oct | 241416213076353 |
9 | 43264284158075 |
10 | 11100111011051 |
11 | 359a592317287 |
12 | 12b333887574b |
13 | 626974c310ba |
14 | 2a536925241d |
15 | 143b155210bb |
hex | a18722c7ceb |
11100111011051 has 2 divisors, whose sum is σ = 11100111011052. Its totient is φ = 11100111011050.
The previous prime is 11100111011039. The next prime is 11100111011113. The reversal of 11100111011051 is 15011011100111.
11100111011051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11100111011051 - 214 = 11100110994667 is a prime.
It is not a weakly prime, because it can be changed into another prime (11100111011251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550055505525 + 5550055505526.
It is an arithmetic number, because the mean of its divisors is an integer number (5550055505526).
Almost surely, 211100111011051 is an apocalyptic number.
11100111011051 is a deficient number, since it is larger than the sum of its proper divisors (1).
11100111011051 is an equidigital number, since it uses as much as digits as its factorization.
11100111011051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5, while the sum is 14.
Adding to 11100111011051 its reverse (15011011100111), we get a palindrome (26111122111162).
The spelling of 11100111011051 in words is "eleven trillion, one hundred billion, one hundred eleven million, eleven thousand, fifty-one".
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