11100111120037 has 2 divisors, whose sum is σ = 11100111120038. Its totient is φ = 11100111120036.

The previous prime is 11100111119989. The next prime is 11100111120047. The reversal of 11100111120037 is 73002111100111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7097034528676 + 4003076591361 = 2664026^2 + 2000769^2 .

It is a cyclic number.

It is not a de Polignac number, because 11100111120037 - 2³⁵ = 11065751381669 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11100111119996 and 11100111120023.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11100111120047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550055560018 + 5550055560019.

It is an arithmetic number, because the mean of its divisors is an integer number (5550055560019).

Almost surely, 2^{11100111120037} is an apocalyptic number.

It is an amenable number.

11100111120037 is a deficient number, since it is larger than the sum of its proper divisors (1).

11100111120037 is an equidigital number, since it uses as much as digits as its factorization.

11100111120037 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 42, while the sum is 19.

Adding to 11100111120037 its reverse (73002111100111), we get a palindrome (84102222220148).

The spelling of 11100111120037 in words is "eleven trillion, one hundred billion, one hundred eleven million, one hundred twenty thousand, thirty-seven".