11100111999973 has 2 divisors, whose sum is σ = 11100111999974. Its totient is φ = 11100111999972.

The previous prime is 11100111999947. The next prime is 11100112000013. The reversal of 11100111999973 is 37999911100111.

11100111999973 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7720629074404 + 3379482925569 = 2778602^2 + 1838337^2 .

It is an emirp because it is prime and its reverse (37999911100111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11100111999973 - 2¹³ = 11100111991781 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11100111999973.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11100111991973) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550055999986 + 5550055999987.

It is an arithmetic number, because the mean of its divisors is an integer number (5550055999987).

Almost surely, 2^{11100111999973} is an apocalyptic number.

It is an amenable number.

11100111999973 is a deficient number, since it is larger than the sum of its proper divisors (1).

11100111999973 is an equidigital number, since it uses as much as digits as its factorization.

11100111999973 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 137781, while the sum is 52.

The spelling of 11100111999973 in words is "eleven trillion, one hundred billion, one hundred eleven million, nine hundred ninety-nine thousand, nine hundred seventy-three".