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1110011212153 is a prime number
BaseRepresentation
bin10000001001110001110…
…100101111000101111001
310221010010120221001001001
4100021301310233011321
5121141300332242103
62205533200325001
7143124053424664
oct20116164570571
93833116831031
101110011212153
11398831433948
1215b164613761
138089abbcc4c
143ba20d086db
151dd1982601d
hex10271d2f179

1110011212153 has 2 divisors, whose sum is σ = 1110011212154. Its totient is φ = 1110011212152.

The previous prime is 1110011212109. The next prime is 1110011212279. The reversal of 1110011212153 is 3512121100111.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 960893983504 + 149117228649 = 980252^2 + 386157^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1110011212153 is a prime.

It is a super-2 number, since 2×11100112121532 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1110011212153.

It is not a weakly prime, because it can be changed into another prime (1110011210153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555005606076 + 555005606077.

It is an arithmetic number, because the mean of its divisors is an integer number (555005606077).

Almost surely, 21110011212153 is an apocalyptic number.

It is an amenable number.

1110011212153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1110011212153 is an equidigital number, since it uses as much as digits as its factorization.

1110011212153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60, while the sum is 19.

Adding to 1110011212153 its reverse (3512121100111), we get a palindrome (4622132312264).

The spelling of 1110011212153 in words is "one trillion, one hundred ten billion, eleven million, two hundred twelve thousand, one hundred fifty-three".