Base | Representation |
---|---|
bin | 10000001001110001111… |
… | …000001100110010011111 |
3 | 10221010010122122011200021 |
4 | 100021301320030302133 |
5 | 121141301100321343 |
6 | 2205533232013011 |
7 | 143124064226266 |
oct | 20116170146237 |
9 | 3833118564607 |
10 | 1110012120223 |
11 | 3988319a4116 |
12 | 15b164991167 |
13 | 8089b14a376 |
14 | 3ba210a35dd |
15 | 1dd199550ed |
hex | 10271e0cc9f |
1110012120223 has 2 divisors, whose sum is σ = 1110012120224. Its totient is φ = 1110012120222.
The previous prime is 1110012120211. The next prime is 1110012120299. The reversal of 1110012120223 is 3220212100111.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1110012120223 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1110012120197 and 1110012120206.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1110012120023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555006060111 + 555006060112.
It is an arithmetic number, because the mean of its divisors is an integer number (555006060112).
Almost surely, 21110012120223 is an apocalyptic number.
1110012120223 is a deficient number, since it is larger than the sum of its proper divisors (1).
1110012120223 is an equidigital number, since it uses as much as digits as its factorization.
1110012120223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 1110012120223 its reverse (3220212100111), we get a palindrome (4330224220334).
The spelling of 1110012120223 in words is "one trillion, one hundred ten billion, twelve million, one hundred twenty thousand, two hundred twenty-three".
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