Base | Representation |
---|---|
bin | 1010000110000111001011… |
… | …0010000100100001100111 |
3 | 1110022011100112101200211001 |
4 | 2201201302302010201213 |
5 | 2423331022013034343 |
6 | 35335154132454131 |
7 | 2223646231420426 |
oct | 241416262044147 |
9 | 43264315350731 |
10 | 11100121221223 |
11 | 359a598060341 |
12 | 12b334017a347 |
13 | 626977097518 |
14 | 2a536a74d2bd |
15 | 143b1638b44d |
hex | a1872c84867 |
11100121221223 has 2 divisors, whose sum is σ = 11100121221224. Its totient is φ = 11100121221222.
The previous prime is 11100121221191. The next prime is 11100121221247. The reversal of 11100121221223 is 32212212100111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11100121221223 - 25 = 11100121221191 is a prime.
It is a super-2 number, since 2×111001212212232 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11100121221223.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11100121225223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550060610611 + 5550060610612.
It is an arithmetic number, because the mean of its divisors is an integer number (5550060610612).
Almost surely, 211100121221223 is an apocalyptic number.
11100121221223 is a deficient number, since it is larger than the sum of its proper divisors (1).
11100121221223 is an equidigital number, since it uses as much as digits as its factorization.
11100121221223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 11100121221223 its reverse (32212212100111), we get a palindrome (43312333321334).
The spelling of 11100121221223 in words is "eleven trillion, one hundred billion, one hundred twenty-one million, two hundred twenty-one thousand, two hundred twenty-three".
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