Base | Representation |
---|---|
bin | 1010000110000111001011… |
… | …0101000101010110111011 |
3 | 1110022011100120212211021112 |
4 | 2201201302311011112323 |
5 | 2423331022213323232 |
6 | 35335154201430535 |
7 | 2223646241220245 |
oct | 241416265052673 |
9 | 43264316784245 |
10 | 11100122011067 |
11 | 359a59854a801 |
12 | 12b334049b44b |
13 | 6269772b2b9b |
14 | 2a536a8b7095 |
15 | 143b164954b2 |
hex | a1872d455bb |
11100122011067 has 2 divisors, whose sum is σ = 11100122011068. Its totient is φ = 11100122011066.
The previous prime is 11100122011019. The next prime is 11100122011079. The reversal of 11100122011067 is 76011022100111.
11100122011067 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11100122011067 - 214 = 11100121994683 is a prime.
It is not a weakly prime, because it can be changed into another prime (11100122011087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550061005533 + 5550061005534.
It is an arithmetic number, because the mean of its divisors is an integer number (5550061005534).
Almost surely, 211100122011067 is an apocalyptic number.
11100122011067 is a deficient number, since it is larger than the sum of its proper divisors (1).
11100122011067 is an equidigital number, since it uses as much as digits as its factorization.
11100122011067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 168, while the sum is 23.
Adding to 11100122011067 its reverse (76011022100111), we get a palindrome (87111144111178).
The spelling of 11100122011067 in words is "eleven trillion, one hundred billion, one hundred twenty-two million, eleven thousand, sixty-seven".
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