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111001300110 = 2325191933171061
BaseRepresentation
bin110011101100000110…
…0010110110010001110
3101121111212112021220100
41213120030112302032
53304312313100420
6122554315031530
711006500324521
oct1473014266216
9347455467810
10111001300110
1143091381768
121961a13b5a6
13a60caa0a8c
14553018cbb8
152d49e84190
hex19d8316c8e

111001300110 has 192 divisors, whose sum is σ = 306619110720. Its totient is φ = 27782922240.

The previous prime is 111001300079. The next prime is 111001300117. The reversal of 111001300110 is 11003100111.

It is a super-2 number, since 2×1110013001102 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (9).

It is a junction number, because it is equal to n+sod(n) for n = 111001300092 and 111001300101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (111001300117) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 104618980 + ... + 104620040.

It is an arithmetic number, because the mean of its divisors is an integer number (1596974535).

Almost surely, 2111001300110 is an apocalyptic number.

111001300110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 111001300110, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (153309555360).

111001300110 is an abundant number, since it is smaller than the sum of its proper divisors (195617810610).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

111001300110 is a wasteful number, since it uses less digits than its factorization.

111001300110 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1603 (or 1600 counting only the distinct ones).

The product of its (nonzero) digits is 3, while the sum is 9.

Adding to 111001300110 its reverse (11003100111), we get a palindrome (122004400221).

The spelling of 111001300110 in words is "one hundred eleven billion, one million, three hundred thousand, one hundred ten".