11100133123 has 2 divisors, whose sum is σ = 11100133124. Its totient is φ = 11100133122.

The previous prime is 11100133081. The next prime is 11100133129. The reversal of 11100133123 is 32133100111.

11100133123 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11100133123 - 2³³ = 2510198531 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11100133097 and 11100133106.

It is not a weakly prime, because it can be changed into another prime (11100133129) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550066561 + 5550066562.

It is an arithmetic number, because the mean of its divisors is an integer number (5550066562).

Almost surely, 2^11100133123 is an apocalyptic number.

11100133123 is a deficient number, since it is larger than the sum of its proper divisors (1).

11100133123 is an equidigital number, since it uses as much as digits as its factorization.

11100133123 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 11100133123 its reverse (32133100111), we get a palindrome (43233233234).

The spelling of 11100133123 in words is "eleven billion, one hundred million, one hundred thirty-three thousand, one hundred twenty-three".