111001332113 has 4 divisors (see below), whose sum is σ = 126858665280. Its totient is φ = 95143998948.

The previous prime is 111001332059. The next prime is 111001332119. The reversal of 111001332113 is 311233100111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311233100111 = 1181 ⋅263533531.

It is a cyclic number.

It is not a de Polignac number, because 111001332113 - 2¹⁴ = 111001315729 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 111001332091 and 111001332100.

It is not an unprimeable number, because it can be changed into a prime (111001332119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7928666573 + ... + 7928666586.

It is an arithmetic number, because the mean of its divisors is an integer number (31714666320).

Almost surely, 2^111001332113 is an apocalyptic number.

It is an amenable number.

111001332113 is a deficient number, since it is larger than the sum of its proper divisors (15857333167).

111001332113 is an equidigital number, since it uses as much as digits as its factorization.

111001332113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15857333166.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 111001332113 its reverse (311233100111), we get a palindrome (422234432224).

The spelling of 111001332113 in words is "one hundred eleven billion, one million, three hundred thirty-two thousand, one hundred thirteen".