1110013404132 has 24 divisors (see below), whose sum is σ = 2616732632416. Its totient is φ = 366189988608.

The previous prime is 1110013404127. The next prime is 1110013404151. The reversal of 1110013404132 is 2314043100111.

It is a junction number, because it is equal to n+sod(n) for n = 1110013404099 and 1110013404108.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 476808718 + ... + 476811045.

Almost surely, 2^{1110013404132} is an apocalyptic number.

1110013404132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

1110013404132 is an abundant number, since it is smaller than the sum of its proper divisors (1506719228284).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1110013404132 is a wasteful number, since it uses less digits than its factorization.

1110013404132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 953619867 (or 953619865 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 1110013404132 its reverse (2314043100111), we get a palindrome (3424056504243).

The spelling of 1110013404132 in words is "one trillion, one hundred ten billion, thirteen million, four hundred four thousand, one hundred thirty-two".