Base | Representation |
---|---|
bin | 10000001001110011000… |
… | …001000100001001010011 |
3 | 10221010011222120121110201 |
4 | 100021303001010021103 |
5 | 121141320443040311 |
6 | 2205535153240031 |
7 | 143124415462534 |
oct | 20116301041123 |
9 | 3833158517421 |
10 | 1110031221331 |
11 | 39884176005a |
12 | 15b16b263017 |
13 | 808a20a75b6 |
14 | 3ba2383668b |
15 | 1dd1b4799c1 |
hex | 10273044253 |
1110031221331 has 4 divisors (see below), whose sum is σ = 1110035640064. Its totient is φ = 1110026802600.
The previous prime is 1110031221301. The next prime is 1110031221413. The reversal of 1110031221331 is 1331221300111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1110031221331 - 213 = 1110031213139 is a prime.
It is a super-2 number, since 2×11100312213312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1110031221299 and 1110031221308.
It is not an unprimeable number, because it can be changed into a prime (1110031221301) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1808280 + ... + 2343061.
It is an arithmetic number, because the mean of its divisors is an integer number (277508910016).
Almost surely, 21110031221331 is an apocalyptic number.
1110031221331 is a deficient number, since it is larger than the sum of its proper divisors (4418733).
1110031221331 is an equidigital number, since it uses as much as digits as its factorization.
1110031221331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4418732.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 1110031221331 its reverse (1331221300111), we get a palindrome (2441252521442).
The spelling of 1110031221331 in words is "one trillion, one hundred ten billion, thirty-one million, two hundred twenty-one thousand, three hundred thirty-one".
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