1110031221413 has 2 divisors, whose sum is σ = 1110031221414. Its totient is φ = 1110031221412.

The previous prime is 1110031221301. The next prime is 1110031221419. The reversal of 1110031221413 is 3141221300111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 570360269284 + 539670952129 = 755222^2 + 734623^2 .

It is an emirp because it is prime and its reverse (3141221300111) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1110031221413 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1110031221419) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555015610706 + 555015610707.

It is an arithmetic number, because the mean of its divisors is an integer number (555015610707).

Almost surely, 2^{1110031221413} is an apocalyptic number.

It is an amenable number.

1110031221413 is a deficient number, since it is larger than the sum of its proper divisors (1).

1110031221413 is an equidigital number, since it uses as much as digits as its factorization.

1110031221413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 1110031221413 its reverse (3141221300111), we get a palindrome (4251252521524).

The spelling of 1110031221413 in words is "one trillion, one hundred ten billion, thirty-one million, two hundred twenty-one thousand, four hundred thirteen".