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11100314121 = 3131914980181
BaseRepresentation
bin10100101011010000…
…10101101000001001
31001122121012101100020
422111220111220021
5140213140022441
65033250131053
7542035053561
oct122550255011
931577171306
1011100314121
114786924326
122199580a89
13107b94b110
14774343da1
1544e7a6e66
hex295a15a09

11100314121 has 16 divisors (see below), whose sum is σ = 16777803840. Its totient is φ = 6471437760.

The previous prime is 11100314053. The next prime is 11100314161. The reversal of 11100314121 is 12141300111.

It is not a de Polignac number, because 11100314121 - 27 = 11100313993 is a prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 11100314121.

It is not an unprimeable number, because it can be changed into a prime (11100314161) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7489350 + ... + 7490831.

It is an arithmetic number, because the mean of its divisors is an integer number (1048612740).

Almost surely, 211100314121 is an apocalyptic number.

It is an amenable number.

11100314121 is a deficient number, since it is larger than the sum of its proper divisors (5677489719).

11100314121 is a wasteful number, since it uses less digits than its factorization.

11100314121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14980216.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 11100314121 its reverse (12141300111), we get a palindrome (23241614232).

It can be divided in two parts, 11100 and 314121, that added together give a triangular number (325221 = T806).

The spelling of 11100314121 in words is "eleven billion, one hundred million, three hundred fourteen thousand, one hundred twenty-one".

Divisors: 1 3 13 19 39 57 247 741 14980181 44940543 194742353 284623439 584227059 853870317 3700104707 11100314121