Base | Representation |
---|---|
bin | 1010000110000111111010… |
… | …1000011100001010110111 |
3 | 1110022011212101110212220002 |
4 | 2201201332220130022313 |
5 | 2423331423411220343 |
6 | 35335225553501515 |
7 | 2223654164255204 |
oct | 241417650341267 |
9 | 43264771425802 |
10 | 11100320023223 |
11 | 359a68a2a5212 |
12 | 12b339687189b |
13 | 6269a9322442 |
14 | 2a5388cdccab |
15 | 143b28a5a8b8 |
hex | a187ea1c2b7 |
11100320023223 has 2 divisors, whose sum is σ = 11100320023224. Its totient is φ = 11100320023222.
The previous prime is 11100320023211. The next prime is 11100320023321. The reversal of 11100320023223 is 32232002300111.
11100320023223 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11100320023223 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11100320023195 and 11100320023204.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11100320026223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550160011611 + 5550160011612.
It is an arithmetic number, because the mean of its divisors is an integer number (5550160011612).
Almost surely, 211100320023223 is an apocalyptic number.
11100320023223 is a deficient number, since it is larger than the sum of its proper divisors (1).
11100320023223 is an equidigital number, since it uses as much as digits as its factorization.
11100320023223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 11100320023223 its reverse (32232002300111), we get a palindrome (43332322323334).
The spelling of 11100320023223 in words is "eleven trillion, one hundred billion, three hundred twenty million, twenty-three thousand, two hundred twenty-three".
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