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111004144403 = 451324596531
BaseRepresentation
bin110011101100001011…
…1001101001100010011
3101121112001212210112112
41213120113031030103
53304314030110103
6122554500015535
711006533442105
oct1473027151423
9347461783475
10111004144403
1143092a44719
121961b0915ab
13a6105585a9
1455306cd575
152d4a346cd8
hex19d85cd313

111004144403 has 4 divisors (see below), whose sum is σ = 111028745448. Its totient is φ = 110979543360.

The previous prime is 111004144397. The next prime is 111004144417. The reversal of 111004144403 is 304441400111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 111004144403 - 222 = 110999950099 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (111004144483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12293753 + ... + 12302778.

It is an arithmetic number, because the mean of its divisors is an integer number (27757186362).

Almost surely, 2111004144403 is an apocalyptic number.

111004144403 is a deficient number, since it is larger than the sum of its proper divisors (24601045).

111004144403 is an equidigital number, since it uses as much as digits as its factorization.

111004144403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24601044.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 111004144403 its reverse (304441400111), we get a palindrome (415445544514).

The spelling of 111004144403 in words is "one hundred eleven billion, four million, one hundred forty-four thousand, four hundred three".

Divisors: 1 4513 24596531 111004144403