Base | Representation |
---|---|
bin | 1010000110001000011110… |
… | …1011100100000010000011 |
3 | 1110022012020222010210222021 |
4 | 2201202013223210002003 |
5 | 2423332231242234203 |
6 | 35335253015422311 |
7 | 2223661016540326 |
oct | 241420753440203 |
9 | 43265228123867 |
10 | 11100471836803 |
11 | 359a757a65a88 |
12 | 12b3419684997 |
13 | 626a0190796b |
14 | 2a53a113a7bd |
15 | 143b370475bd |
hex | a1887ae4083 |
11100471836803 has 2 divisors, whose sum is σ = 11100471836804. Its totient is φ = 11100471836802.
The previous prime is 11100471836761. The next prime is 11100471836813. The reversal of 11100471836803 is 30863817400111.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11100471836803 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11100471836803.
It is not a weakly prime, because it can be changed into another prime (11100471836813) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550235918401 + 5550235918402.
It is an arithmetic number, because the mean of its divisors is an integer number (5550235918402).
Almost surely, 211100471836803 is an apocalyptic number.
11100471836803 is a deficient number, since it is larger than the sum of its proper divisors (1).
11100471836803 is an equidigital number, since it uses as much as digits as its factorization.
11100471836803 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96768, while the sum is 43.
The spelling of 11100471836803 in words is "eleven trillion, one hundred billion, four hundred seventy-one million, eight hundred thirty-six thousand, eight hundred three".
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