Base | Representation |
---|---|
bin | 10000001001110100010… |
… | …010000101100111100111 |
3 | 10221010020110112200212021 |
4 | 100021310102011213213 |
5 | 121141341412223111 |
6 | 2205541232404011 |
7 | 143125064144053 |
oct | 20116422054747 |
9 | 3833213480767 |
10 | 1110052461031 |
11 | 398852747828 |
12 | 15b1763a6607 |
13 | 808a6603077 |
14 | 3ba265a4c63 |
15 | 1dd1d272d71 |
hex | 102744859e7 |
1110052461031 has 2 divisors, whose sum is σ = 1110052461032. Its totient is φ = 1110052461030.
The previous prime is 1110052461019. The next prime is 1110052461151. The reversal of 1110052461031 is 1301642500111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1110052461031 - 25 = 1110052460999 is a prime.
It is a super-2 number, since 2×11100524610312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1110052460987 and 1110052461005.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1110052431031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555026230515 + 555026230516.
It is an arithmetic number, because the mean of its divisors is an integer number (555026230516).
Almost surely, 21110052461031 is an apocalyptic number.
1110052461031 is a deficient number, since it is larger than the sum of its proper divisors (1).
1110052461031 is an equidigital number, since it uses as much as digits as its factorization.
1110052461031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 25.
Adding to 1110052461031 its reverse (1301642500111), we get a palindrome (2411694961142).
The spelling of 1110052461031 in words is "one trillion, one hundred ten billion, fifty-two million, four hundred sixty-one thousand, thirty-one".
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