Base | Representation |
---|---|
bin | 11001001111011010000111… |
… | …100111011111101110000000 |
3 | 112120001110012202202100121000 |
4 | 121033122013213133232000 |
5 | 104022241440000310422 |
6 | 1032033142345132000 |
7 | 32245131200122200 |
oct | 3117320747375600 |
9 | 476043182670530 |
10 | 111010000010112 |
11 | 3240a092a87755 |
12 | 1054a59448a000 |
13 | 49c327625bc38 |
14 | 1d5acac510400 |
15 | cc7958d39cac |
hex | 64f6879dfb80 |
111010000010112 has 384 divisors, whose sum is σ = 381228259104000. Its totient is φ = 31708540910592.
The previous prime is 111010000010089. The next prime is 111010000010141. The reversal of 111010000010112 is 211010000010111.
It is a tau number, because it is divible by the number of its divisors (384).
It is a Harshad number since it is a multiple of its sum of digits (9).
It is a junction number, because it is equal to n+sod(n) for n = 111010000010094 and 111010000010103.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 637831839 + ... + 638005857.
It is an arithmetic number, because the mean of its divisors is an integer number (992781924750).
Almost surely, 2111010000010112 is an apocalyptic number.
111010000010112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 111010000010112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (190614129552000).
111010000010112 is an abundant number, since it is smaller than the sum of its proper divisors (270218259093888).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
111010000010112 is a wasteful number, since it uses less digits than its factorization.
111010000010112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 177823 (or 177798 counting only the distinct ones).
The product of its (nonzero) digits is 2, while the sum is 9.
Adding to 111010000010112 its reverse (211010000010111), we get a palindrome (322020000020223).
Subtracting 111010000010112 from its reverse (211010000010111), we obtain a palindrome (99999999999999).
The spelling of 111010000010112 in words is "one hundred eleven trillion, ten billion, ten thousand, one hundred twelve".
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