Base | Representation |
---|---|
bin | 10000001001110111001… |
… | …100000011101101101101 |
3 | 10221010100212021111122012 |
4 | 100021313030003231231 |
5 | 121141441402241023 |
6 | 2205550133331005 |
7 | 143126225420153 |
oct | 20116714035555 |
9 | 3833325244565 |
10 | 1110101212013 |
11 | 3988782150a2 |
12 | 15b18a796a65 |
13 | 808b3741ac1 |
14 | 3ba2cc553d3 |
15 | 1dd226a2978 |
hex | 10277303b6d |
1110101212013 has 2 divisors, whose sum is σ = 1110101212014. Its totient is φ = 1110101212012.
The previous prime is 1110101211959. The next prime is 1110101212061. The reversal of 1110101212013 is 3102121010111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 953362818409 + 156738393604 = 976403^2 + 395902^2 .
It is a cyclic number.
It is not a de Polignac number, because 1110101212013 - 28 = 1110101211757 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1110101212813) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555050606006 + 555050606007.
It is an arithmetic number, because the mean of its divisors is an integer number (555050606007).
Almost surely, 21110101212013 is an apocalyptic number.
It is an amenable number.
1110101212013 is a deficient number, since it is larger than the sum of its proper divisors (1).
1110101212013 is an equidigital number, since it uses as much as digits as its factorization.
1110101212013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 14.
Adding to 1110101212013 its reverse (3102121010111), we get a palindrome (4212222222124).
The spelling of 1110101212013 in words is "one trillion, one hundred ten billion, one hundred one million, two hundred twelve thousand, thirteen".
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