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111010130013 = 337003376671
BaseRepresentation
bin110011101100010111…
…0000010100001011101
3101121112111010220020210
41213120232002201131
53304322043130023
6122555232203033
711006635351626
oct1473056024135
9347474126223
10111010130013
1143096362802
1219621099479
13a611872b83
14553140aa4d
152d4ab2a593
hex19d8b8285d

111010130013 has 4 divisors (see below), whose sum is σ = 148013506688. Its totient is φ = 74006753340.

The previous prime is 111010130009. The next prime is 111010130041. The reversal of 111010130013 is 310031010111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 111010130013 - 22 = 111010130009 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (111010130093) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18501688333 + ... + 18501688338.

It is an arithmetic number, because the mean of its divisors is an integer number (37003376672).

Almost surely, 2111010130013 is an apocalyptic number.

It is an amenable number.

111010130013 is a deficient number, since it is larger than the sum of its proper divisors (37003376675).

111010130013 is an equidigital number, since it uses as much as digits as its factorization.

111010130013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 37003376674.

The product of its (nonzero) digits is 9, while the sum is 12.

Adding to 111010130013 its reverse (310031010111), we get a palindrome (421041140124).

The spelling of 111010130013 in words is "one hundred eleven billion, ten million, one hundred thirty thousand, thirteen".

Divisors: 1 3 37003376671 111010130013