Base | Representation |
---|---|
bin | 110011101100010111… |
… | …0011000100001110011 |
3 | 101121112111022110220002 |
4 | 1213120232120201303 |
5 | 3304322104021042 |
6 | 122555234140215 |
7 | 11006636205461 |
oct | 1473056304163 |
9 | 347474273802 |
10 | 111010220147 |
11 | 430964144a2 |
12 | 1962112166b |
13 | a6118a4bc8 |
14 | 5531431831 |
15 | 2d4ab47132 |
hex | 19d8b98873 |
111010220147 has 2 divisors, whose sum is σ = 111010220148. Its totient is φ = 111010220146.
The previous prime is 111010220089. The next prime is 111010220149. The reversal of 111010220147 is 741022010111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 111010220147 - 228 = 110741784691 is a prime.
Together with 111010220149, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (111010220149) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55505110073 + 55505110074.
It is an arithmetic number, because the mean of its divisors is an integer number (55505110074).
Almost surely, 2111010220147 is an apocalyptic number.
111010220147 is a deficient number, since it is larger than the sum of its proper divisors (1).
111010220147 is an equidigital number, since it uses as much as digits as its factorization.
111010220147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 112, while the sum is 20.
Adding to 111010220147 its reverse (741022010111), we get a palindrome (852032230258).
The spelling of 111010220147 in words is "one hundred eleven billion, ten million, two hundred twenty thousand, one hundred forty-seven".
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