Base | Representation |
---|---|
bin | 1010000110001010110100… |
… | …0111110110101010010011 |
3 | 1110022020212202011022210002 |
4 | 2201202231013312222103 |
5 | 2423340023100311011 |
6 | 35335435215400215 |
7 | 2224012415116415 |
oct | 241425507665223 |
9 | 43266782138702 |
10 | 11101100010131 |
11 | 359aa4a60699a |
12 | 12b3573b2306b |
13 | 626aa1ab8c61 |
14 | 2a54207389b5 |
15 | 143b7227cc3b |
hex | a18ad1f6a93 |
11101100010131 has 2 divisors, whose sum is σ = 11101100010132. Its totient is φ = 11101100010130.
The previous prime is 11101100010101. The next prime is 11101100010149. The reversal of 11101100010131 is 13101000110111.
11101100010131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11101100010131 - 26 = 11101100010067 is a prime.
It is a super-2 number, since 2×111011000101312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11101100010101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550550005065 + 5550550005066.
It is an arithmetic number, because the mean of its divisors is an integer number (5550550005066).
Almost surely, 211101100010131 is an apocalyptic number.
11101100010131 is a deficient number, since it is larger than the sum of its proper divisors (1).
11101100010131 is an equidigital number, since it uses as much as digits as its factorization.
11101100010131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3, while the sum is 11.
Adding to 11101100010131 its reverse (13101000110111), we get a palindrome (24202100120242).
The spelling of 11101100010131 in words is "eleven trillion, one hundred one billion, one hundred million, ten thousand, one hundred thirty-one".
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