Base | Representation |
---|---|
bin | 110011101100011000… |
… | …1010110111101010011 |
3 | 101121112112210002211222 |
4 | 1213120301112331103 |
5 | 3304322304001042 |
6 | 122555302555255 |
7 | 11006645634515 |
oct | 1473061267523 |
9 | 347475702758 |
10 | 111011000147 |
11 | 430968a7523 |
12 | 19621438b2b |
13 | a611ab8c48 |
14 | 5531595bb5 |
15 | 2d4ac4d2d2 |
hex | 19d8c56f53 |
111011000147 has 2 divisors, whose sum is σ = 111011000148. Its totient is φ = 111011000146.
The previous prime is 111011000071. The next prime is 111011000173. The reversal of 111011000147 is 741000110111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 111011000147 - 214 = 111010983763 is a prime.
It is not a weakly prime, because it can be changed into another prime (111011000447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55505500073 + 55505500074.
It is an arithmetic number, because the mean of its divisors is an integer number (55505500074).
Almost surely, 2111011000147 is an apocalyptic number.
111011000147 is a deficient number, since it is larger than the sum of its proper divisors (1).
111011000147 is an equidigital number, since it uses as much as digits as its factorization.
111011000147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 28, while the sum is 17.
Adding to 111011000147 its reverse (741000110111), we get a palindrome (852011110258).
The spelling of 111011000147 in words is "one hundred eleven billion, eleven million, one hundred forty-seven", and thus it is an aban number.
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