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11101111100143 is a prime number
BaseRepresentation
bin1010000110001010110111…
…0010001010001011101111
31110022020220112000202102021
42201202231302022023233
52423340033420201033
635335440253211011
72224012611306001
oct241425562121357
943266815022367
1011101111100143
11359aa558a0a99
1212b3577790a67
13626aa419c9ac
142a5421dc4371
15143b7321db2d
hexa18adc8a2ef

11101111100143 has 2 divisors, whose sum is σ = 11101111100144. Its totient is φ = 11101111100142.

The previous prime is 11101111100087. The next prime is 11101111100153. The reversal of 11101111100143 is 34100111110111.

11101111100143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11101111100143 - 225 = 11101077545711 is a prime.

It is a super-3 number, since 3×111011111001433 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11101111100153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550555550071 + 5550555550072.

It is an arithmetic number, because the mean of its divisors is an integer number (5550555550072).

Almost surely, 211101111100143 is an apocalyptic number.

11101111100143 is a deficient number, since it is larger than the sum of its proper divisors (1).

11101111100143 is an equidigital number, since it uses as much as digits as its factorization.

11101111100143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 16.

Adding to 11101111100143 its reverse (34100111110111), we get a palindrome (45201222210254).

The spelling of 11101111100143 in words is "eleven trillion, one hundred one billion, one hundred eleven million, one hundred thousand, one hundred forty-three".