111011198124049 has 2 divisors, whose sum is σ = 111011198124050. Its totient is φ = 111011198124048.

The previous prime is 111011198124031. The next prime is 111011198124067. The reversal of 111011198124049 is 940421891110111.

It is a balanced prime because it is at equal distance from previous prime (111011198124031) and next prime (111011198124067).

It can be written as a sum of positive squares in only one way, i.e., 108892042468225 + 2119155655824 = 10435135^2 + 1455732^2 .

It is a cyclic number.

It is not a de Polignac number, because 111011198124049 - 2²³ = 111011189735441 is a prime.

It is a super-2 number, since 2×111011198124049² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 111011198123996 and 111011198124014.

It is not a weakly prime, because it can be changed into another prime (111011198124089) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55505599062024 + 55505599062025.

It is an arithmetic number, because the mean of its divisors is an integer number (55505599062025).

Almost surely, 2^{111011198124049} is an apocalyptic number.

It is an amenable number.

111011198124049 is a deficient number, since it is larger than the sum of its proper divisors (1).

111011198124049 is an equidigital number, since it uses as much as digits as its factorization.

111011198124049 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20736, while the sum is 43.

The spelling of 111011198124049 in words is "one hundred eleven trillion, eleven billion, one hundred ninety-eight million, one hundred twenty-four thousand, forty-nine".