Base | Representation |
---|---|
bin | 10100101011010111… |
… | …00010100111001101 |
3 | 1001122122210001002021 |
4 | 22111223202213031 |
5 | 140213343404431 |
6 | 5033320130141 |
7 | 542045151466 |
oct | 122553424715 |
9 | 31578701067 |
10 | 11101153741 |
11 | 4787348127 |
12 | 2199906951 |
13 | 107bb83332 |
14 | 7744c1d6d |
15 | 44e8c0b11 |
hex | 295ae29cd |
11101153741 has 2 divisors, whose sum is σ = 11101153742. Its totient is φ = 11101153740.
The previous prime is 11101153729. The next prime is 11101153751. The reversal of 11101153741 is 14735110111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9671935716 + 1429218025 = 98346^2 + 37805^2 .
It is a cyclic number.
It is not a de Polignac number, because 11101153741 - 25 = 11101153709 is a prime.
It is a super-2 number, since 2×111011537412 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11101153751) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550576870 + 5550576871.
It is an arithmetic number, because the mean of its divisors is an integer number (5550576871).
Almost surely, 211101153741 is an apocalyptic number.
It is an amenable number.
11101153741 is a deficient number, since it is larger than the sum of its proper divisors (1).
11101153741 is an equidigital number, since it uses as much as digits as its factorization.
11101153741 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 420, while the sum is 25.
Adding to 11101153741 its reverse (14735110111), we get a palindrome (25836263852).
The spelling of 11101153741 in words is "eleven billion, one hundred one million, one hundred fifty-three thousand, seven hundred forty-one".
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