Base | Representation |
---|---|
bin | 11001001111011011111110… |
… | …111101001111101010001111 |
3 | 112120001122101022020011001201 |
4 | 121033123332331033222033 |
5 | 104022310040030401312 |
6 | 1032034113151050331 |
7 | 32245231621345123 |
oct | 3117337675175217 |
9 | 476048338204051 |
10 | 111012002200207 |
11 | 3240aa2018a809 |
12 | 1054aa52b109a7 |
13 | 49c3504cc20c4 |
14 | 1d5b01c3b9583 |
15 | cc7a249d1557 |
hex | 64f6fef4fa8f |
111012002200207 has 2 divisors, whose sum is σ = 111012002200208. Its totient is φ = 111012002200206.
The previous prime is 111012002200171. The next prime is 111012002200213. The reversal of 111012002200207 is 702002200210111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 111012002200207 - 231 = 111009854716559 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111012002200217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55506001100103 + 55506001100104.
It is an arithmetic number, because the mean of its divisors is an integer number (55506001100104).
Almost surely, 2111012002200207 is an apocalyptic number.
111012002200207 is a deficient number, since it is larger than the sum of its proper divisors (1).
111012002200207 is an equidigital number, since it uses as much as digits as its factorization.
111012002200207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112, while the sum is 19.
Adding to 111012002200207 its reverse (702002200210111), we get a palindrome (813014202410318).
The spelling of 111012002200207 in words is "one hundred eleven trillion, twelve billion, two million, two hundred thousand, two hundred seven".
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