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11101221111083 is a prime number
BaseRepresentation
bin1010000110001011010001…
…0101110100010100101011
31110022021012012000220001112
42201202310111310110223
52423340300101023313
635335455223140535
72224015415344415
oct241426425642453
943267165026045
1011101221111083
1135a00019aa924
1212b35a85a474b
13626ac0c0a01c
142a543285d9b5
15143b7cbee8a8
hexa18b457452b

11101221111083 has 2 divisors, whose sum is σ = 11101221111084. Its totient is φ = 11101221111082.

The previous prime is 11101221111059. The next prime is 11101221111139. The reversal of 11101221111083 is 38011112210111.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11101221111083 is a prime.

It is a super-2 number, since 2×111012211110832 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11101221117083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550610555541 + 5550610555542.

It is an arithmetic number, because the mean of its divisors is an integer number (5550610555542).

Almost surely, 211101221111083 is an apocalyptic number.

11101221111083 is a deficient number, since it is larger than the sum of its proper divisors (1).

11101221111083 is an equidigital number, since it uses as much as digits as its factorization.

11101221111083 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 23.

Adding to 11101221111083 its reverse (38011112210111), we get a palindrome (49112333321194).

The spelling of 11101221111083 in words is "eleven trillion, one hundred one billion, two hundred twenty-one million, one hundred eleven thousand, eighty-three".