Base | Representation |
---|---|
bin | 1010000110001011010001… |
… | …0101110100010100101011 |
3 | 1110022021012012000220001112 |
4 | 2201202310111310110223 |
5 | 2423340300101023313 |
6 | 35335455223140535 |
7 | 2224015415344415 |
oct | 241426425642453 |
9 | 43267165026045 |
10 | 11101221111083 |
11 | 35a00019aa924 |
12 | 12b35a85a474b |
13 | 626ac0c0a01c |
14 | 2a543285d9b5 |
15 | 143b7cbee8a8 |
hex | a18b457452b |
11101221111083 has 2 divisors, whose sum is σ = 11101221111084. Its totient is φ = 11101221111082.
The previous prime is 11101221111059. The next prime is 11101221111139. The reversal of 11101221111083 is 38011112210111.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11101221111083 is a prime.
It is a super-2 number, since 2×111012211110832 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11101221117083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550610555541 + 5550610555542.
It is an arithmetic number, because the mean of its divisors is an integer number (5550610555542).
Almost surely, 211101221111083 is an apocalyptic number.
11101221111083 is a deficient number, since it is larger than the sum of its proper divisors (1).
11101221111083 is an equidigital number, since it uses as much as digits as its factorization.
11101221111083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 23.
Adding to 11101221111083 its reverse (38011112210111), we get a palindrome (49112333321194).
The spelling of 11101221111083 in words is "eleven trillion, one hundred one billion, two hundred twenty-one million, one hundred eleven thousand, eighty-three".
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