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111012301313 is a prime number
BaseRepresentation
bin110011101100011011…
…0010100101000000001
3101121112122020012201022
41213120312110220001
53304323122120223
6122555350515225
711006662664144
oct1473066245001
9347478205638
10111012301313
1143097606071
1219621965b15
13a612153274
14553181405b
152d4ae08ac8
hex19d8d94a01

111012301313 has 2 divisors, whose sum is σ = 111012301314. Its totient is φ = 111012301312.

The previous prime is 111012301291. The next prime is 111012301441. The reversal of 111012301313 is 313103210111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 109953254464 + 1059046849 = 331592^2 + 32543^2 .

It is an emirp because it is prime and its reverse (313103210111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111012301313 - 26 = 111012301249 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 111012301291 and 111012301300.

It is not a weakly prime, because it can be changed into another prime (111012306313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55506150656 + 55506150657.

It is an arithmetic number, because the mean of its divisors is an integer number (55506150657).

Almost surely, 2111012301313 is an apocalyptic number.

It is an amenable number.

111012301313 is a deficient number, since it is larger than the sum of its proper divisors (1).

111012301313 is an equidigital number, since it uses as much as digits as its factorization.

111012301313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 111012301313 its reverse (313103210111), we get a palindrome (424115511424).

The spelling of 111012301313 in words is "one hundred eleven billion, twelve million, three hundred one thousand, three hundred thirteen".