Base | Representation |
---|---|
bin | 1010000110001011010011… |
… | …1101001001001011011011 |
3 | 1110022021012220102122101211 |
4 | 2201202310331021023123 |
5 | 2423340310220420443 |
6 | 35335500232123551 |
7 | 2224015602102055 |
oct | 241426475111333 |
9 | 43267186378354 |
10 | 11101231420123 |
11 | 35a0007801199 |
12 | 12b35abb365b7 |
13 | 626ac30a9450 |
14 | 2a5433d848d5 |
15 | 143b7da8919d |
hex | a18b4f492db |
11101231420123 has 16 divisors (see below), whose sum is σ = 12235335429856. Its totient is φ = 10007233931520.
The previous prime is 11101231420117. The next prime is 11101231420127. The reversal of 11101231420123 is 32102413210111.
11101231420123 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 11101231420123 - 241 = 8902208164571 is a prime.
It is a super-2 number, since 2×111012314201232 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11101231420094 and 11101231420103.
It is not an unprimeable number, because it can be changed into a prime (11101231420127) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1476193 + ... + 4937773.
It is an arithmetic number, because the mean of its divisors is an integer number (764708464366).
Almost surely, 211101231420123 is an apocalyptic number.
11101231420123 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
11101231420123 is a deficient number, since it is larger than the sum of its proper divisors (1134104009733).
11101231420123 is a wasteful number, since it uses less digits than its factorization.
11101231420123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3467374.
The product of its (nonzero) digits is 288, while the sum is 22.
Adding to 11101231420123 its reverse (32102413210111), we get a palindrome (43203644630234).
The spelling of 11101231420123 in words is "eleven trillion, one hundred one billion, two hundred thirty-one million, four hundred twenty thousand, one hundred twenty-three".
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