Base | Representation |
---|---|
bin | 10000001001111001000… |
… | …001111011001101111111 |
3 | 10221010110000102021222202 |
4 | 100021321001323031333 |
5 | 121142022310011312 |
6 | 2205553155502115 |
7 | 143130052146311 |
oct | 20117101731577 |
9 | 3833400367882 |
10 | 1110132110207 |
11 | 3988936a939a |
12 | 15b198bb793b |
13 | 808b9c6c863 |
14 | 3ba32db97b1 |
15 | 1dd252579c2 |
hex | 1027907b37f |
1110132110207 has 2 divisors, whose sum is σ = 1110132110208. Its totient is φ = 1110132110206.
The previous prime is 1110132110203. The next prime is 1110132110237. The reversal of 1110132110207 is 7020112310111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1110132110207 - 22 = 1110132110203 is a prime.
It is a super-2 number, since 2×11101321102072 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1110132110203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555066055103 + 555066055104.
It is an arithmetic number, because the mean of its divisors is an integer number (555066055104).
Almost surely, 21110132110207 is an apocalyptic number.
1110132110207 is a deficient number, since it is larger than the sum of its proper divisors (1).
1110132110207 is an equidigital number, since it uses as much as digits as its factorization.
1110132110207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 84, while the sum is 20.
Adding to 1110132110207 its reverse (7020112310111), we get a palindrome (8130244420318).
The spelling of 1110132110207 in words is "one trillion, one hundred ten billion, one hundred thirty-two million, one hundred ten thousand, two hundred seven".
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