Base | Representation |
---|---|
bin | 10100101011011000… |
… | …01011100001100001 |
3 | 1001122200002112221122 |
4 | 22111230023201201 |
5 | 140213414240223 |
6 | 5033323502025 |
7 | 542046450155 |
oct | 122554134141 |
9 | 31580075848 |
10 | 11101321313 |
11 | 4787452015 |
12 | 2199987915 |
13 | 107bc116a4 |
14 | 774527065 |
15 | 44e9055c8 |
hex | 295b0b861 |
11101321313 has 2 divisors, whose sum is σ = 11101321314. Its totient is φ = 11101321312.
The previous prime is 11101321279. The next prime is 11101321339. The reversal of 11101321313 is 31312310111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10673369344 + 427951969 = 103312^2 + 20687^2 .
It is an emirp because it is prime and its reverse (31312310111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11101321313 - 28 = 11101321057 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11101321291 and 11101321300.
It is not a weakly prime, because it can be changed into another prime (11101321393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550660656 + 5550660657.
It is an arithmetic number, because the mean of its divisors is an integer number (5550660657).
Almost surely, 211101321313 is an apocalyptic number.
It is an amenable number.
11101321313 is a deficient number, since it is larger than the sum of its proper divisors (1).
11101321313 is an equidigital number, since it uses as much as digits as its factorization.
11101321313 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 11101321313 its reverse (31312310111), we get a palindrome (42413631424).
The spelling of 11101321313 in words is "eleven billion, one hundred one million, three hundred twenty-one thousand, three hundred thirteen".
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