11101890119153 has 2 divisors, whose sum is σ = 11101890119154. Its totient is φ = 11101890119152.

The previous prime is 11101890119147. The next prime is 11101890119183. The reversal of 11101890119153 is 35191109810111.

11101890119153 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9695607205729 + 1406282913424 = 3113777^2 + 1185868^2 .

It is a cyclic number.

It is not a de Polignac number, because 11101890119153 - 2¹⁴ = 11101890102769 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11101890119153.

It is not a weakly prime, because it can be changed into another prime (11101890119123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550945059576 + 5550945059577.

It is an arithmetic number, because the mean of its divisors is an integer number (5550945059577).

Almost surely, 2^{11101890119153} is an apocalyptic number.

It is an amenable number.

11101890119153 is a deficient number, since it is larger than the sum of its proper divisors (1).

11101890119153 is an equidigital number, since it uses as much as digits as its factorization.

11101890119153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9720, while the sum is 41.

Adding to 11101890119153 its reverse (35191109810111), we get a palindrome (46292999929264).

The spelling of 11101890119153 in words is "eleven trillion, one hundred one billion, eight hundred ninety million, one hundred nineteen thousand, one hundred fifty-three".