11101890119147 has 2 divisors, whose sum is σ = 11101890119148. Its totient is φ = 11101890119146.

The previous prime is 11101890119123. The next prime is 11101890119153. The reversal of 11101890119147 is 74191109810111.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11101890119147 is a prime.

It is a super-2 number, since 2×11101890119147² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11101890119098 and 11101890119107.

It is not a weakly prime, because it can be changed into another prime (11101890119107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550945059573 + 5550945059574.

It is an arithmetic number, because the mean of its divisors is an integer number (5550945059574).

Almost surely, 2^{11101890119147} is an apocalyptic number.

11101890119147 is a deficient number, since it is larger than the sum of its proper divisors (1).

11101890119147 is an equidigital number, since it uses as much as digits as its factorization.

11101890119147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18144, while the sum is 44.

Adding to 11101890119147 its reverse (74191109810111), we get a palindrome (85292999929258).

The spelling of 11101890119147 in words is "eleven trillion, one hundred one billion, eight hundred ninety million, one hundred nineteen thousand, one hundred forty-seven".